+ 13
How to break nested loops in Python
If there are two loops in which one loop is inside another loop.So how can i can both loop at once condition.
38 odpowiedzi
+ 84
Adarsh Srivastava here is solution.
for i in range(0,6):
for z in range(0,6):
if(z==2):
break #break inner loop.
else:
print(z)
if(i==2):
break #break outer loop.
+ 9
Maninder Singh thanku very much ..
+ 7
var = False
while '''condition''':
#do smth
while '''condition''':
#do smth
if '''you need to break the loop''':
var = True
break
if var: #or 'if var == True', no difference
break
+ 5
I would recommend checking out this Stackoverflow question on this as some of the answers explain how to do so quite well - https://stackoverflow.com/questions/189645/how-to-break-out-of-multiple-loops-in-JUMP_LINK__&&__python__&&__JUMP_LINK
+ 2
By using the break statement in the second loop
+ 2
Adarsh Srivastava here is solution.
for g in range(0,7):
for a in range(0,7):
if(a==4):
break
else:
print(a)
if(g==3):
break
Hope this will help you.
1st break inner loop and the outter loop.
+ 1
Rosy can you please add your clear code here?
+ 1
✅ refactor the nested loop into a function and use return to break out .
+ 1
for i in range (0,n):
for j in range (0, m):
break # Exit nested loops
+ 1
stop = False
pip = [ 100, 200, 300]
while not(stop) :
for x in pip :
if x < 300 :
print("lower")
else :
print("higher")
stop = True (that to break while loop )
break functions can be used in state of the variable (stop) to break:
(1) all the loop :
remove stop variable , add break in the last of code outside for loop and inside while loop .
(2) for loop only :
remove stop variable , add break in the last of code inside for loop .
the first way make code complicate.
the second way make it more clearer .
use DRY principle .
+ 1
a= 0
while True:
print("loop" )
a= a + 1
if a >= 5:
print("Breaking")
break
+ 1
Use break statement to break two loop
+ 1
Inside the for loop you can use break keyword to terminate the loop how ever if you want to skip particular number or case you can use continue keyword
+ 1
for var in range(parameter):
for i in range(parameter):
if i == j :
break
else:
print(i)
if i==k:
break
0
I still did not manage to skip the even number in the fizzbuzz code challenge, can someone explain to me how to break the loop without stopping after 1
0
You need to use the 'continue' operator to skip everything that is written in the loop after it and go straight to the next iteration of the loop.
0
We can skip the even numbers by given range(1,n,2)
0
var = False
while '''condition''':
#do smth
while '''condition''':
#do smth
if '''you need to break the loop''':
var = True
break
if var: #or 'if var == True', no difference
break
0
This can be done by using "break" keyword
0
for i in range(1, 10):
if i == 5: # when i is 5 exit the loop
break
print("i =", i)
print("break out")