- 5

bruh

Fill in the blanks to define a function that prints "Yes", if its parameter is an even number, and "No" otherwise. even(x): if x%2 == 0: ("Yes") print("No")

helpplzandquickhatethisplzhelpnowstufff
1st Oct 2020, 3:32 PM
Isaiah Hudson
Isaiah Hudson - avatar
1 Risposta
- 3
plz help me
1st Oct 2020, 3:34 PM
Isaiah Hudson
Isaiah Hudson - avatar

Hai spesso domande come questa?

Impara in modo più efficiente, gratuitamente:

Vedi tutti i corsi
Popolare oggi
Is it possible to convert .zip file to apk? If yes, how??
1 Votes
Pointers cpp
2 Votes
I think the heart system is ridiculous, 5 hearts that refill after like 5 hours? That is really just crazy to me.
1 Votes
What do you think of this code and what are your suggestions for developing and modifying it?, How can I develop myself more?
0 Votes
Why can’t I use double “ in python?
0 Votes
Is pro worth the money ?
1 Votes
2 cases not correct what's the problem
1 Votes
Drawing images in java
2 Votes
You’re free to give me your advice! 🚨
0 Votes
Coding for Cybersecurity
0 Votes