FIZZBUZZ QUESTION

Question

It takes an input n and outputs the numbers from 1 to n.
For each multiple of 3, print "Solo" instead of the number.
For each multiple of 5, prints "Learn" instead of the number.
For numbers which are multiples of both 3 and 5, output "SoloLearn".

You need to change the code to skip the even numbers, so that the logic only applies to odd numbers in the range.

Answer 1

Denise Roßberg My program starts from 1 in all conditions and goes up to the number entered by user. Since all odd numbers are required, I am updating value of i with 2

Answer 2

Adi Nath Bhawani

Ah, okay. Now I got it. 👍

Answer 3

Hello Sheikh Mohammed Ahmedraza

Please show us your code so that we can help you.

Answer 4

n=int(input("Enter number"))
for i in range(1,n+1,2):
if(i%15==0):
print("SoloLearn")
elif(i%5==0):
print("Learn")
elif(i%3==0):
print("Solo")
else:
print(i)

Answer 5

n = int(input())

for x in range(1, n):
if x % 3 == 0 and x % 5 == 0:
print("SoloLearn")
elif x % 3 == 0:
print("Solo")
elif x % 5 == 0:
print("Learn")
else:
print(x)
continue

>>>>this is the given code, we have to correct or edit it to get correct answer

Answer 6

Sheikh Mohammed Ahmedraza

Add the beginning you need to check if x % 2 == 0

if x % 2 == 0:
continue
elif...

You need to put it at the beginning because e.g. 6 is divible by 3

btw: you can simplify x%3 and x%5 to x%15

elif x%15:

Answer 7

Adi Nath Bhawani

I would say your code won't work if you enter an even number.
e.g. 10, then it gets 12, 14....

Answer 8

you should first exclude the even numbers

n = int(input())

for x in range(1, n):
if x % 2 == 0:
continue
elif x % 3 == 0 and x % 5 == 0:
print("SoloLearn")
elif x % 3 == 0:
print("Solo")
elif x % 5 == 0:
print("Learn")
else:
print(x)