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Cout<<x endl;
0 Votos
1 Respuesta#include <iostream>
using namespace std;
int sum(int a, int b=42) {
int result = a + b;
return (result);
}
int main() {
int x = 24;
int y = 36;
//calling the function with both parameters
int result = sum(x, y);
cout << result << endl;
//calling the function without b
result = sum(x);
cout << result << endl;
return 0;
}
why is da last function cout 66 and not 48 isn't it suppose to add 24+24?
1 Voto
6 Respuestasdouble arr[]={5,2,7,8,11,9};
int n = sizeof(arr) / sizeof(arr[0]);
double sum = 0;
for(int i=0;i<n;i++)
{
sum+= arr[i];
}
double avg = sum / n;
cout<< "avarage ="<< avg<< endl;
return 0;
)
/*what does int n= sizeof(arr[]) /sizeof(arr[0]);
do, can someone explain that line for me*/
0 Votos
3 Respuestaswhat is tjis code problem!
#include <iostream>
using namespace std;
int main()
{
int b = 5;
int arr[b] = {11, 35, 62, 555, 989};
int sum = 0;
for (int x = 0; x < 5; x++) {
sum += arr[x];
}
cout << sum << endl;
return 0;
}
I cannot make an array using int variable in order to define array's element number!?
1 Voto
7 Respuestaswhat will be output??
#include <iostream>
using namespace std;
int main(int a)
{
cout << a << "\n";
return 0;
}
int main(char *a)
{
cout << a << endl;
return 0;
}
int main(int a, int b)
{
cout << a << " " << b;
return 0;
}
int main()
{
main(3);
main("Subodh");
main(9, 6);
return 0;
}
if output is compilation compilation error then how can we overload "main" function in C++
0 Votos
5 RespuestasWY I get a rundum number from memory when I run this code
#include <iostream>
using namespace std;
int main ()
{
int array [5];
for (int x = 0; x < 5; x++) {
array [x] = 42;
cout << x << ': ' << array [x] << endl;
}
return 0;
}
if I replace ': ' with ": " every thing works well.
0 Votos
2 RespuestasWher is mistake?
0 Votos
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