+ 1

# return vs cout in C++

int func(int x, int y) { x = 10; return (x+y); } int main () { int i = 0; int j = 5; i = func (j, i); cout << i << j; } I'm confused about how the return statement is used in the code above. I first assigned i = func(5,0) ----> have no idea what to do next... do I add 5 and 0 and re-assign i = 5? Also, where would I plug in the x = 10 in the second line? How does x and y relate to i and j? Is the final output provided by cout, return (x+y) or int func(int x, int y)? Totally lost.

22nd Jul 2020, 7:23 AM
Solus
3 Respuestas
+ 4
Solus Is this something you wrote? Here are the answers to your questions: 1. The return statement is, well, returning the integer value 10 from func(5, 0). 2. func(5, 0) ignores the first argument as x is always reassigned the value 10. Therefore, func(5, 0) will return (10 + 0) instead of (5 + 0) which is then assigned to int i in the main function. 3. You asked "where do you plug in x = 10 in the second line?" Did you mean "why" instead of "where"? Assuming you meant "why", I would say you would know better than me if you wrote this code. 😉 However, if you grabbed this code from code challenges, then it's likely the author was trying to make this a tricky question. 🤷‍♂️ 4. The values j and i are passed as the input arguments x and y for func(x, y). Notice the reverse order of j and i, which map to x and y as illustrated below: x = j y = i 5. i is assigned 10 as the return value from func(5, 0). j is still 5. cout prints 10, then 5 without spaces which appears as: 105
22nd Jul 2020, 7:59 AM
David Carroll
+ 3
@David Carroll As a beginner, how would I know that the return statement return (x+y) will return the integer value 10 from i = func(5, 0)? If i = 10, then cout will indeed output 105. But I still don't really understand how i = 10 came to be... This was a challenge Q that I got wrong. I'm trying to learn from my mistakes. Thank you for the explanation.
22nd Jul 2020, 8:27 AM
Solus
+ 1
Return type returns the value It doesn't print value means you can assign returned value to other variable.Whereas Cout Simply prints text.
22nd Jul 2020, 7:41 AM
Akash
En tendencia hoy
Help me!!