Separating a number into integral and fractional part

Question

How to separate for example 12.345 into its integral part and fractional part? like integral part is 12 and fractional part is 0.345 in C++?

Answer 1

Daniel
I wish you linked your attempts on this problem in this post.

https://www.sololearn.com/post/75089/?ref=app

Anyways,

What part feels you hard make in this?

It's really simple.
Just go with your own given example.

double n = 12.345;

12.345
/ \
/ \
12. 0.345

As you can see for integer part you have to skip part after decimal point.
For this you can typecast your `double` or `float` to `int`
Typecast it and store in a variable.
int integer_part=(int)n;

Next the fractional part can be obtained by dividing integer part from fractional number.

12.345 - 12 =0.345;

For this

double fractional_part = n - integer_part;

Keep practicing.

Answer 2

You can try function `modf` from cmath header:

Reference (example included)
http://www.cplusplus.com/reference/cmath/modf/

Answer 3

Daniel
Well done ~

The problem is that you should take input for variable before you do any calculations using it. Otherwise it will contain some random(garbage) value.
https://www.sololearn.com/Discuss/1654860/?ref=app

So all you need to do is write line 10 and 11 after declaration of `n`.

And don't forget to print values of `integer_part` and `fractional_part`
Not using them ,you'll get warning by SL compiler.

Answer 4

🇮🇳Omkar🕉 //Busy , Exams. how about if i want the user to input any number not just static number? is it the same?

Answer 5

Ipang i try to implement that

Answer 6

Daniel ,
Yes . it's same even if you try with user inputs.

Answer 7

🇮🇳Omkar🕉 //Busy , Exams.
https://code.sololearn.com/c9OCKwu3jPzi/?ref=app why i cant use the cin for n?