+ 2

# How do i make this more concise?

basic math function. takes 2 integers as a range and returns a Boolean statement for each integer in that range based on a division statment of a 3rd input integer having a 0 remainder value. https://code.sololearn.com/c52jl0i80LM4/?ref=app edit: with thanks to visph for cleaning up the junk I posted. The link now points to the updated version, and possibly later updates as well.

15th Apr 2017, 10:26 PM
Michael Van Meter
1 Answer
+ 8
# To be more concise: # - don't use new variables to get the range # - test if per==0 instead use try/finally (all the most if you doesn't use 'catch' statement # - don't need to use str(div) as 'div' is already a String type ^^ # - your 'percentfinder' function doesn't return any value, so you don't need to call it with an assignment to a 'pfind' variable (and anyway, you should 'print(pfind)' to display it's value :P) def percentfinder(rg,rge,per): if per==0: print("Cannot divide by 0.") return for i in range(rg,rge+1): if int(i)%per==0: div="" else: div=" not" print (str(i)+" is"+div+" divisable by "+str(per)) ab=int(input()) bc=int(input()) cd=int(input()) percentfinder(ab,bc,cd)
16th Apr 2017, 4:40 AM
visph