How to make a 3 case switch statement in javascript?

Question

#bool1
#bool2
#bool3
#int
# switch(true){
Case1: int = 0
Case2: int = 1
Case3: int = 2
}
If all bool are true
Then output must be
0
1
2
0
1
2
# If any two bool are true then switching must be like
1
2
1
2
(bool2 and bool3 are true and bool1 is false )

#If one bool true
Then no switch statement should execute

Let's discuss
😸
I've made few logic gates too but they ain't working as i needed

Answer 1

Shubh is this your actual output correct ?
mode is start mode, execute=6

true true true
mode = 0
1,2,0,1,2,0
true true false
mode = 0
1,0,1,0,1,0
true false true
mode = 0
2,0,2,0,2,0
true false false
mode = 0
0,0,0,0,0,0
false true true
mode = 1
2,1,2,1,2,1
false true false
mode = 1
1,1,1,1,1,1
false false true
mode = 2
2,2,2,2,2,2
false false false
mode = 0
0,0,0,0,0,0

Answer 2

Shubh

Java or JavaScript?

Answer 3

A͢J offcourse javascript I'd mentioned there already

Answer 4

Shubh

You have mentioned Java also in tag.

There is no int in JavaScript, there is only var

Answer 5

Shubh

If bool1 and bool2 are true and bool3 is false then what should be the output?

Answer 6

Shubh

As switch accept only one value at a time so you can call switch 2 times:

Note : switch don't accept boolean value.

Here is a one solution just for hint

var bool1 = true
var bool2 = true
var bool3 = false

function print(x) {
switch (x) {
case 0:
console.log(0);
case 1:
console.log(1);
case 2:
console.log(2);
}
}

if (bool1 && bool2 && bool3) {
print(0)
print(0)
}

if (bool1 && bool2 && !bool3
|| bool2 && bool3 && !bool1) {
print(1)
print(1)
}

Answer 7

In hurry i tagged java
By int i meant integer

Answer 8

If any two boolean are true then output should be
Like
1
0
1
0
1
0

Answer 9

var bool1 = false;
var bool2 = true;
var bool3 = false;
var execute = 10;
var mode = null;

if(mode==null)
{
switch(true)
{
case (bool1): mode = 0; break;
case (bool2): mode = 1; break;
case (bool3): mode = 2; break;
default: mode = 0; break;
}
}
for(var x = 0;x<execute;x++)
{
switch(true){

case(bool1 && bool2 && bool3):

switch(mode){
case 0: mode = 1; console.log(mode); break;
case 1: mode = 2; console.log(mode); break;
case 2: mode = 0; console.log(mode); break;
}; break;
case(bool3 && bool2):

switch(mode){
case 1: mode = 2; console.log(mode); break;
case 2: mode = 1; console.log(mode); break;
}; break;
case(bool3 && bool1):

switch(mode){
case 0: mode = 2; console.log(mode); break;
case 2: mode = 0; console.log(mode); break;
}; break;
case(bool1 && bool2):

switch(mode){
case 1: mode = 0; console.log(mode); break;
case 0: mode = 1; console.log(mode); break;
}; break;
default: console.log(mode); break;
}
}

Answer 10

I made this

Answer 11

Just a little optimization is needed

Answer 12

https://code.sololearn.com/WHGAevI76h85/?ref=app

Answer 13

Here

Answer 14

zemiak exactly that's the output i want..
Just take an example of mode switching in a gun
If it has auto then 0
Single then 1
And burst then 2
As some have all 3 modes
Some have only two modes like single n burst for handguns
N some have only one mode
So am creating an gun script for my game engine
N just wanting the code to be as optimised as it could

Answer 15

Each bool holds a different represention if an exterior function

Answer 16

https://www.sololearn.com/discuss/3052041/?ref=app

Answer 17

zemiak here is the logic gate i got