+ 3

# Help with code (array)

Hello. Can someone help me understand why the output for this program is 6? static void Main(string[] args) { int[,] array = new int[2,2] {{1,1}, {2,1}}; int mult = 1; for(int i =0; i<2; ++i){ int sum=0; for(int j=0; j<2; ++j){ sum+=array[i,j]; } mult*=sum; } Console.WriteLine(mult); //output is 6

31st Mar 2017, 3:00 PM
Elena
+ 13
// Please, for the love of cookies, enforce proper indentations. int[,] array = new int[2,2] {{1,1}, {2,1}}; int mult = 1; for (int i =0; i<2; ++i) { int sum=0; for(int j=0; j<2; ++j) { sum+=array[i,j]; } mult*=sum; } // for first loop, i is 0, sum gets added with 1 and 1 when j is 0 and j is 1 respectively, to become 2. This is then multiplied into mult. Variable mult now stores 2. // for second loop, i is 1, sum gets reinitialised to 0, and then added with 2 and 1 when j is 0 and j is 1 respectively, to become 3. This is then multiplied into mult. Variable mult becomes 2 * 3, which is 6. // code outputs mult, which outputs 6.
31st Mar 2017, 3:18 PM
Hatsy Rei
+ 5
Thank you very much
31st Mar 2017, 3:17 PM
Elena
+ 5
Here are some cookies for the help. đȘ đȘ đȘ
31st Mar 2017, 5:45 PM
Elena
+ 4
first mult = 1; when i = 0: sum = 0 j = 0 >> array[0,0] = 1 >> sum = 0 + 1 = 1; j = 1 >> array[0,1] = 1 >> sum = 1 + 1 = 2; then mult = 1 * 2 = 2; and when i = 1: sum back to zero j = 0 >> array[1,0] = 2 >> sum = 0 + 2 = 2; j = 1 >> array[1,1] = 1 >> sum = 2 + 1 = 3; then mult = 2 * 3 = 6; I hope you get it
31st Mar 2017, 3:14 PM
Abdullah Alshaibany