+ 2

# as far as of my assumption this loop will be infinite then how i m getting the result. i would appreciate any help.

public class Program { public static void main(String[] args) { int result = 0; for(int i = 0;i<8;i--) { if(i==7){ result +=3; }else{ result +=i; } } System.out.println(result); } }

30th Mar 2017, 1:14 PM
shobhit + 1
looks like you guys haven't understood my question.my question is that that in the else statement it is programed that result is 'result + i' but i m decrementing the 'i' so it will be decremented infinitely and result+i will also run infinitely so how i m getting the result.
30th Mar 2017, 5:18 PM
shobhit + 17
shobhit maybe u could set the For Loop to execute a specific number of times.. or adjust the initial i-condition (i<8) to something like: (i<8 && i !<0), in other words, i less than 8 AND i NOT less than zero. plz let me know how your problem turns out.. i don't undetstand, but just couldn't resist trying thanks
31st Mar 2017, 3:16 PM
niteOwLTwO + 17
shobhit to me, it looks like result remains zero after the first pass: i=0. result=0, !(i==7) so (result+=i) evaluates tp 0.. the For loop could be set to run a specific numbet of times or maybe the conditipn
31st Mar 2017, 3:22 PM
niteOwLTwO 0
your code have no chance to be 7 rather it decreases down to neg Infinity, and holds true for the condition (i<8), and hence loops forever, simply incrementing the value of result by i. I tried to eliminate the infinite loop, try it as follows if I got your question correctly. public class Program { public static void main(String[] args) { int result = 0; for(int i = 0;i<8;i++) { if(i==7){ result +=3; }else{ result +=i; } } System.out.println(result); } } result will become 0+1+2+3+4+5+6+3=24, and the output is 24.
30th Mar 2017, 1:38 PM
WONDE-TOM 