+ 1

# Find the sum of these following series.

1. 1 + 1/1! + 1/2! + 1/3! + .................. 2. x - xĂx/2! + xĂxĂx/3! - xĂxĂxĂx/4! + xĂxĂxĂxĂx/5! - ................... 3. x + xĂx/2 + xĂxĂx/3 + xĂxĂxĂx/4 + xĂxĂxĂxĂx/5 + ............... Pls Answer immediately ....

4 Answers

+ 14

After thinking a lot:
1234598765đđđđ

+ 7

1. e
2. 1-e^(-x) maybe
3.log(1+x)

+ 7

It's hard to write the whole program. So, here's how you can do it.
1) Define a function for factorial.
2) Scan x.
3) Use a loop from n=1 to (a large number)
(ii) sum += pow(-1, n+1) * pow(x, n) / fact(n);
(iii) sum += pow(x, n) / fact(n);

+ 4

The first one is a common equivalence to e (2.71828...)
The second one is the Taylor expansion for e^x.
The third one is the Taylor expansion for
-ln(1-x).