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# How can plus 1 to 100 odd number (use for i in range(1,101))

sum=0 for i in range(1,101): sum=sum+i

6 Answers

+ 2

sum([i for i in range(1, 101) if i % 2])

+ 2

use
if(i%2 !=0)
sum = sum + i;
@abhishek

+ 1

for (i=1;i<=100;i++)
{
if (i%2!=0)
sum=sum+i;
}
This code is for C language

+ 1

is it ok to use (i%2==1) instead of (i%2!=0)??

+ 1

print(sum( [ i for i in range(1,100,2)]))

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sum = 0
for i in range(1,101):
if (i % 2 != 0):
sum = sum + i
print(sum)