21st Sep 2020, 3:35 AM
Smiley[Offline]
4 Answers
+ 2
Start reading from string_mult = second(first(2,1),2) in order to solve this start by solving first(2,1) which is 2*1 =2 now you replace first(2,1) with 2 Now you have second(2,2) which is 2+2 =4 then you have your string_mult =4 Lets go now to chars = strinf_mult * 'a' Which is 4*'a' = aaaa In the end you take length of aaaa which is 4 of course first and second are anonymous functions declared in this way function_name=lambda argument1, argumant2 : return statement
21st Sep 2020, 3:46 AM
Ruba Kh
Ruba Kh - avatar
0
There is no code. Check if it is in private mode.
21st Sep 2020, 3:37 AM
Lucas Kliemczak
Lucas Kliemczak - avatar
21st Sep 2020, 3:39 AM
Smiley[Offline]
0
I found out that opening the link in a PC is different of opening with a mobile.
21st Sep 2020, 9:49 AM
Lucas Kliemczak
Lucas Kliemczak - avatar