How can I write a program that take a n(a positive number)as input,make n×n list then return the 0 and 1 into spiral.
Your attempt ? EDIT (her answer): Yes This is my code but it isn't compelete n=int(input("enter a n")) L= for i in range(n): L.append(*n) for row in L: for i in range(n): L[i]=1 L[n_1][i]=1 L[i][n_1]=1 L[i]=1 L=0
fatemeh salmani I used almot the same method. You have to find a way to get all the indexes that will be changed to 1. Here is a hint: This how it iterates: 1) [0, 0] -> [0, n-1] -> [n-1, n-1] -> [n-1, 0] -> [2, 0], then add [2, 1] 2) [2, 2] -> [2, n-1-2] -> [n-1-2, n-1-2] -> [n-1-2, 2] -> [4, 2], then add [2, 1] 3) [4, 4] -> [4, n-1-4] -> [n-1-4, n-1-4] -> [n-1-4, 4] -> [6, 5], then add [6, 5] Try to find the pattern
fatemeh salmani I wrote a working script, but it is using generators and functions. I think it is overcomplicated, there must be an easier way to do it. I'll try to find another solution, or wait for someone to share his own solution. NOTE: For people who don't know what the output should be like, try my code to get an idea. (contact me for the link)