Q. Python Exception
except TypeError as e: print(e) Is it possible to do the same for except: So that i can get a brief description about the error.
You can do it in a more general way, without naming each exception in detail: number = '3' try: result = number + 10 except Exception as e: print('Error:',e) # output: "Error: must be str, not int"
No, you can't. With last example you just detect existence of an error, but dont actually get it