what will be the output of: int x=1; x=x++ + x++; cout<<x;

Answer 1

acc to me it should be 3 because it will do as follows 1+2. First it will take x=1 as it is post fix and then as 2. So total will be 3.
Can someone just confirm ??

Answer 2

Yeah!!! Programmer is right!... writing x++ + x ++ its like (((x)++) + x) which gives 1 + 2 that is equal to 3 and then again x++ that leave x equal to 3 but this last result is overwriten with the result from 1 + 2 that in this case is also 3.
If you have x++ + x ++ + x++ you will have 1 + 2 + 3 and with x = 4 after the third post-increment, but that value is overwriten by the result from the operatiob that is equal to 6... so at the end x equals 6...
I haven't notice that behaviour before... it's all about operator precedence... thanks programmer for open my eyes... ;-)

Answer 3

3

Answer 4

++x is pahle increase karo & phir use
x++ is use karo & then value increase karo aage k liye.

Answer 5

deepak
its (x++) + (x++)
Got it!!

Answer 6

yup it returns 3..? but how?

Answer 7

how can it be 4 ??

Answer 8

x=(1+1)+(1+1)
x=4
right?

Answer 9

tanx

Answer 10

I think it is 2

Answer 11

x+++x++; ??

Answer 12

I guess it should be 4.... but just for curiosity y run it in the Code Playground and got 3 as an output... so, I was driven to think that if you have several post-increment in the same statement for the same variable, only one is considered... but then I did another test with x = x++ + x++ + x++; and got 6 as the output....!!!????
So, I guess the code ground compiler it's not close to be perfect... ;-)

Answer 13

x+++ can be equivalent to x+2