x=x+(3*2)

Question

x=2 and result is 8,but they write 7

Answer 1

#include <stdio.h>

int main() {
int x = 2;

x += 1; // x is now 3
x -= 1; // x is now 2
x *= 3; // x is now 6
x /= 2; // x is now 3
x %= 2; // x is now 1
x += 3 * 2; // x is now 7

printf("%d", x);

return 0;
}

Answer 2

But x has changed value to 1.

Answer 3

x was 2, but it changed value.

Answer 4

...
x %= 2; // x=1
x += 3*2; // x+=6

1 + 6 == 7

Answer 5

Are you sure you didn't type x+(2+3)?

Answer 6

#include <stdio.h>

int main() {
int x = 2;

x += 1; // 3
x -= 1; // 2
x *= 3; // 6
x /= 2; // 3
x %= 2; // 1
x += 3 * 2; // 7

printf("%d", x);

return 0;
}

Answer 7

int x=2; it's condition

Answer 8

😀Thanks

Answer 9

If x = 2 then x=x+(2*3) = 8

2*3=6+2= 8