What is wrong with this code?

Question

#include<iostream>
using namespace std;

int main()
{ int n,x=0;
int arr[x];

cout<<"introdusca un numero: ";
cin>>n;

while(n!=0){

cout<<"introdusca un numero: ";
cin>>n;

arr[x]=n;
x++;
}

cout<<arr[x];

return 0;}

/* my objective is to crate a code that when I introduce difference number, it save them but if the number is zero then the code "cout" the numbers that I input before the zero. please help.*\

Answer 1

When you create the array, you must assign the complete length. Since the length is 0, you can not add to it.

Answer 2

Iterate over the elements
for(int i=0;i < arr.length;i++){
cout << arr[i];
}

Answer 3

Exacto, lo que dijo Ariela.
Cuando creas un array, debes especificar que tan grande será.
int arr[50];

es posible hacerlo sin establecer un numero determinado de elementos desde un principio, pero implica utilizar vector y alocar memoria dinamicamente.

Por ahora, puedes establecer tus arrays con un numero determinado de elementos, por ejemplo 75 ya que probablemente no vayas a ingresar mas de 75 numeros.

Suerte!

Answer 4

/*finally we got it, millions of thanks. this is the code: *\

#include<iostream>
using namespace std;

int main()
{ int n=3,x=0;
int arr[75];

while(n!=0){

cout<<"introdusca un numero: ";
cin>>n;

arr[x]=n;
x++;
}

for(int i=0;i <=x; i++){
cout <<endl<< arr[i];
}

return 0;
}

Answer 5

thanks I got it, but now how can I "cout " the whole array? mi idioma original es el español.

Answer 6

thank Ariela I just was trying something more or less like that:

#include<iostream>
using namespace std;

int main()
{ int n,x=0;
int arr[75];

cout<<"introdusca un numero: ";
cin>>n;

while(n!=0){

cout<<"introdusca un numero: ";
cin>>n;

arr[x]=n;
x++;
}

for(int t=-1; t!=x; t++){

cout<<arr[t];cout<<endl;

}

return 0;
}

it almost worked but I will try with your method.