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Liferay platform - Free resources?
javaliferayportal
5 Votes
5 Answers
7th Jan 2019, 8:38 AM
Paolo De Nictolis
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ConducciĂłn de calor o Q=−kAdTdxQ = -k A \frac{dT}{dx}Q=−kAdxdT o Pared 2 mÂČ, espesor 0.1 m, k = 50 W/m°C, ΔT = 30°C → Q ≈ 30,0
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