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after_codecodecode_in_real_lifejob_requirment
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1st Jun 2023, 2:31 PM
Shimaa
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ConducciĂłn de calor o Q=−kAdTdxQ = -k A \frac{dT}{dx}Q=−kAdxdT o Pared 2 mÂČ, espesor 0.1 m, k = 50 W/m°C, ΔT = 30°C → Q ≈ 30,0
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