in nested 'if' . why dos 'if' statement is execute the first answer, even there is some right answer in below. why is work in first come first serve, if I wanted to get more answer in an 'if' state ment is it possible in python | Sololearn: Learn to code for FREE!
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in nested 'if' . why dos 'if' statement is execute the first answer, even there is some right answer in below. why is work in first come first serve, if I wanted to get more answer in an 'if' state ment is it possible in python

13th Nov 2016, 7:42 PM
Arun karthick
Arun karthick - avatar
2 Answers
+ 2
You're asking about this problem: num=7 if num > 3: print("3") if num < 5: print("5") if num ==7: print("7") Answer: Because num is not less than 5; the test for 7 can actually never be true. In separate "if" statements, this logic is: if num > 3: print("3") if (num > 3) and (num < 5): # You must include the context from the previous "if" print("5") if (num > 3) and (num < 5) and (num == 7): print("7") It is impossible for the third "if" statement to ever be true (you could call this a bug).
13th Nov 2016, 10:02 PM
Kirk Schafer
Kirk Schafer - avatar
0
The thing to understand is that Python is lazy : in an 'if' statement, if the condition evaluated to True, then Python will NEVER go further.
13th Nov 2016, 8:03 PM
Amaras A
Amaras A - avatar