when x++ exactly increment the value of var?

Question

Hi all. I've problem with x++ and its that when exactly it increase the value of var.
ie:
x=1;
y=2+x+4*(x++)+3*(x++*5);
what will happen here?
is it correct to say that the second sentence mean
y=2+x+4*x+3*x*5;x+=2;
or
y=2+x+4*x+3//now x_new=x+1; then continue *(x_new*5);

Answer 1

each time the command x++ is evaluated, the program takes the current value of x for its calculation and after that increment the x value

in the confusing code above x++ occurs twice

y=2+x+4*( x++ )+3*( x++ *5);
^ ^
evaluated evaluated
as 1 and as 2 and
then incremented
incremented to 3
to 2

so the final value of y could be portrayed as
2+1+4*(1)+3*(2*5) = 37
and the final value of x is 3

Answer 2

dude no need to panic when it is a=x++ it will first give the value of x to a and then add 1 and if its a=++x then it will first add 1 and then give value of x to a.It is explained in simple words if you understood then like :-)