What's wrong with this code?

Question

x=[23,45,65]
y=[24,46,66]
print('min',min(x[:1],y[:1]))

Answer 1

There is nothing wrong with your code it's working fine. What you code is actually doing finding the minimum element value in two lists x and y

x [:1] this line of code is giving range to list x. If you put x [:6] it means you are giving a range to list from 0 to 6. List will go through from index 0 to 6

print('min',min(x[:1],y[:1]))

This statement will print minimum number in these list which is 23

Answer 2

There's no way to tell since you've omitted the code's intent (the definition of a 'logical' error; but humans can guess when computers can't). Here's what it does:

>>> x=[23,45,65]
>>> y=[24,46,66]
>>> print('min',min(x[:1],y[:1]))
min [23]

If you check the inside steps:

>>> print(x[:1])
[23]
>>> print(y[:1])
[24]
>>>

It's a human guess this is a logical error since you're only comparing the first value in each list. The computer doesn't care (but it can be made to with Asserts).

Answer 3

@Waqas Asghar

There's nothing wrong with the syntax; it's probably a logical error.

There's no range() call. The : operator omits the indicated value ( :6 is 0-5). The minimum printed is between 2 values (those two at index 0), not all 6.

Like...this minimum should probably be 0:

>>> x=[23,45,65,1,2,3]
>>> y=[24,46,66,0,190,7]]
>>> print('min',min(x[:1],y[:1]))
min [23]

Unless the OP omitted a loop to return the minimum at each index (0-5, here).