int main() {int i=4; i=++i-i++ +(2*i); if(i>10) i=i+(--i); cout<<i;

Question

please explain the working

Answer 1

i=4 next 5-5 in the next + (2*6 )because increments i =6 and first do it multiplication and later add and result is 12.
12 > 10.
i=i +(--i);
i=12+11;
output 23.
If I'm wrong I'll be greatful for improve.

Answer 2

I think at the first equation, i becomes 5-5 + (2*5). So 10. After that i gets incremented because of i++. So it becomes 11. After that i becomes 10-10 = 0. I did this in my head, I might be wrong. What's the output?