Output is 4 how ?

Question

#include <iostream>
using namespace std;
typedef int (*fpointer)(int,int);
int f1(int x,int y){return x+y;}
int f2(int x,int y){return x-y;}
fpointer getFunc(int x){
if(x==1)
return f1;
if(x==2)
return f2;
}
int main() {
cout<<getFunc(1)(2,2);

return 0;
}

Answer 1

cout << getFunc(1)(2, 2);
getFunc(1) => x == 1 is true => f1 is returned.

cout << f1(2, 2);
f1(2, 2) => 2 + 2 = 4 is returned.

So, 4 is the output.

Answer 2

@krishna Teja yeluripati thanks

Answer 3

your name is too long ...

Answer 4

#include <iostream>
using namespace std;
int *fun(){
return new int[2];
}
int fun(int*p){
delete[]p;
return 0;
}
void fun (int*p,int q){
p[q]*=2;
}
void fun(int*p,int q,int r){
p[q]=r;
}
int main() {
int *v=fun();
fun(v,0,1);
fun(v,1,2);
fun(v,0);
cout<<v[1]+v[0];
fun(v);
return 0;
}
this program is giving error please find output

Answer 5

~swim~ wow awesome very nice explain thank-you very much

Answer 6

~swim~ i fixed error now please tell me how to come output 4?