Tell me why does this print 1 instead of 0?

Question

int sum = 0,bum = 0;
for(int i = 1;i <= 5;++i) {
sum += i;
System.out.println(i);
}
for(int i = 1;i <= 5;i++) {
bum += i;
System.out.println(i);
}
if(sum == bum) {
System.out.println("1");
} else {
System.out.println("0");
}
How does I++ and ++I work here?.

Answer 1

because both conditions (a.k.a finish line) are :
less than or equal to 5 , which is :
1+2+3+4+5 at the end of both sum or bum.

regardless the plus-ing step , same finish line :
++i or i++ , different only seen in specific condition.

try this too :

int i,j;
i=0;
j=0;
System.out.println(i);
System.out.println(++i);
if(i==0)System.out.println("ouch");
System.out.println(j);
System.out.println(j++);
if(j==0)System.out.println("LoL");

hope helps.

Answer 2

so, you want to say that it doesnt really do anything different in this case?

Answer 3

Difference between ++i and i++ matters only if used in a same instruction. For example if(1>i++) is not same than if(1>++i).