What will be output of following program ?

Question

int main()
{
int a=5,b=10,c;

int *p=&a, *q=&b;

c=p-q;

printf("%d",c);

return 0;

}

what is the ans of above program

Answer 1

good to get to know that brother
thanks ..✌

Answer 2

C is 3 in VC++ ide. It just tell you that a and b are 3 memory blocks apart. It is kind of platform dependant.

Answer 3

Dear Shivshankar it is all about memory offset.

Answer 4

@sayan
pointers don't work like normal integers, so you can't add them.
you can only add an int to then.
subtraction of two pointers will give you the number of items (int In this case) in between them, instead of the difference of the raw pointer values.

Answer 5

what is the outpur of above program

Answer 6

out put will be 1...

Answer 7

#sayan chandra how we get to 1 plzz comment fast

Answer 8

ok babak sheykhan

Answer 9

tysm sayan chandra

Answer 10

The answer is undefined. It depends on the compiler used. Will probably be 1 (or -1) but not necessarily.

Answer 11

the output is 1...showing...
for any values of a,b

Answer 12

the thing is..
its showing as &a=-12 &b=-14
p=-12 and q=-14
but c =1

Answer 13

but out put of p and q is -12 & -14
c=p-q
how is c=1 ???
and yes...printing c as q-p it results -1
BUT c=p+q shows invalid pointer addition