can anyone explain this code

Question

following is the code for addition of two numbers without using arithematic operators..
main()
{
int x,y,result;
x=2;
y=5;
char *p=0;
result=(int)&((&(p[x]))[y]);
printf("sum=%d",result);

Answer 1

p==0
p[x] == *(p+x) so &(p[x]) == p+x == x
x[y] == *(x+y) so &(x[y]) == x+y (which was cast as a pointer)
x+y is then cast as an int, which is 7 and then displayed