How much HCL can be prepared when 5 gram of hydrogen react with an excess amount of chlorine. Eauation is h2+cl2 to 2hcl

Answer 1

You already have the equation.

H2 + Cl2 -> 2HCl

mole = mass/(molar mass)

One mole of H2 can react with one mole of Cl2 to produce two moles of HCl. Information given: 5 gram of H2. Chlorine given in excess, so it's not a limiting factor.

mole of H2 = 5/2
mole of HCl produced = 2 * 5/2 = 5

mass of HCl produced = 5 * molar mass of HCl = 5 * (1+35.5) ≈ 182.5g

Answer 2

Edit: Eh, I don't really know. I didn't read it and I'm not that into chemistry. While chemi's part of STEM and this might be your homework, this is a coding forum and you aren't providing any context in that direction.

Answer 3

thanks alotttttt

Answer 4

yes

Answer 5

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Answer 6

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