Can anyone help me with this code?

Question

int x, y, z;
y=6;
x=5;
z=3;
if(y%z)
cout<<--x;
else
cout<<x--;

Output is 5.
Now I can't understand the if statement!?

Answer 1

This Language Is C++

y%z is "0"

IF without a comparison operator automatically becomes a Boolean.
so...

if(y%z) means if "0" is "True" write "4"

else write "5"

And since "0" is "False" the output becomes "5"

try this one to get 4

int x, y, z;
y=6;
x=5;
z=3;
if(y%x)
cout<<--x;
else
cout<<x--;

Answer 2

@Divam it's like this if you want to make it more understandable: if(y%z==1)

and if u mean the result of (y%z) you're right it's zero

Answer 3

@Usopp, It's C++

Answer 4

@Divam, "YES" That would give "4"

Answer 5

@Nomeh Uchenna Gabriel

What language is this?

Answer 6

@Nomeh Uchenna Gabriel

Thanks

Answer 7

Means, we can also say that the statement is like this, if(y%z=0)