Explain me this.

Question

int x = 0;
switch(x) {
case 1:
System.out.print(1);
case 0:
System.out.print(1);
case 2:
System.out.print(3);
}

Why does this code output 13 instead of 1?

Answer 1

Essentially what is happening is a fall through. Not using breaks is a method of having multiple cases run one block / multiple blocks of code.

As soon as one condition is met, it will execute all blocks below that case if there are no breaks or until it reaches a break.

Answer 2

Because you have not added a break statement at the end of each case. So it will go through every statement and output the result of the final statement.

fix:
case...
statements...
break;
case...
Statements...
break;

Answer 3

@Mark No, if it's false, it won't be executed.So:

int a = 3;
switch (a){
case 2:
System.out.println(2);
case 3:
System.out.println(3);
case 4:
System.out.println(4);
}
//34

Answer 4

@Hassie you take my answers away😊😂

Answer 5

wait, even if the statements are false it will output the other statements?

Answer 6

@Jonas awe 😀

Answer 7

that's the best answer i've ever heard in my life