Is this assigning bark with "woof"?

Question

public class Dog{

static void bark(){System.out.println("woof");}
}

thanks

Answer 1

This is a void function 'bark' which prints "woof" to the console. It is different from assigning a value to a variable. A function contains a block of code which is executed when the function is called.

Answer 2

Within the main itself you will have to instantiate dog object and make a call to bark function.

Dog d = new Dog();
d.bark();

Answer 3

This would work too. I am not creating a separate object here but only calling the function bark from main

public class Program
{
public static void main(String[] args) {
bark();

}

static void bark(){System.out.println("woof");

}
}

Answer 4

how come i can call it from main without it being assigned using Dog.bark();?

Answer 5

@ apoorva i can do this without having to instantiate dog object i can just do dog.bark(); and it works??

would doing it your way allow me to change bark(); to somthing else if i was going to create another animal?