+ 9
Can anyone explain the output ?
//~~ first code ~~ #include <iostream> using namespace std; int main() { int i=0; for(;i<=4;i++) i*=6; cout<<i; return 0; } //output 7 // ~~ second code ~~ #include <iostream> using namespace std; int main() { int i=0; for(;i<=4;i++); i*=6; cout<<i; return 0; } //output 30 //in the second code( i )will be 5 from the for loop and then multiply by 6 , so the output is 30 , am I right ?
3 Answers
+ 3
You are correct.
In the first code i starts off as 0
then (0 <= 4) => true
0 * 6 = 0
++i, i becomes 1
(1 <= 4) => true
1 * 6 = 6
++i, i becomes 7
(7 <= 4) => false
Done
+ 9
Ahh , Now it is clear ,thank you so much @Dennis.
+ 7
here I was thinking that [i] would stop incrementing at 4.
Edit: Clearly it does not. Adds another for good measure ;l
https://code.sololearn.com/cp043va9GuW5/?ref=app