How to check an element to be in an array or not in C++?

Question

listStr = ["hi", "hello", "bye"]
elt = "hi"
if elt in listStr :
print("yes")
else:
print("no")

Answer 1

//https://code.sololearn.com/cQwlCmY1xAPN/#cpp

#include <iostream>

using namespace std;

int main() {

string listStr[] = {"hi", "hello", "bye"};

string elt = "hi";
int x = 0;

for(int i = 0; i < sizeof(listStr) / sizeof(listStr[0]); i++) {
if (listStr[i] == elt) {
cout << "yes" << endl;
} else {
x++;
}

if (x == sizeof(listStr) / sizeof(listStr[0])) {
cout << "no" << endl;
}
}

return 0;
}

Answer 2

tks