How to do this in C++?

Question

input: "abh"
output: "a"
"b"
"h"

Answer 1

std::string theString = "abcd";
std::vector<char> vChar(theString.begin(), theString.end())
for(unsigned int i = 0; i < vChar.size(); i++) {
std::cout << vChar[i] << std::endl;
}

**** There is probably an easier way to do this ****

Answer 2

#include <iostream>
using namespace std;

int main() {

char x[3];

cin>>x[0]>>x[1]>>x[2];

cout<<x[0]<<endl<<x[1]<<endl<<x[2];

return 0;
}

Answer 3

//I made some modifications :

#include <iostream>
using namespace std;

int main() {

char x[1000];

for(int i=0; i<1000; i++)

cin>>x[i];

for(int i=0; i<x[i]; i++)

cout<<x[i]<<endl;

return 0;
}

//....@Nguyen . Now I can input 1000 characters :)

Answer 4

#include<iostream>
#include<string>
using namespace std;

int main() {

string str;
getline(cin, str);

for (int i =0 ; i < str.length(); i++)
cout << str.at(i)<<"\n";

system("pause");
return 0;
}

//I'm not good at English

Answer 5

@Nguyên . Yes , I know just this way to input characters , but now I understand your code .

maybe my way is hard , but easy to understand :|

Answer 6

@Nguyên . what is the purpose of system in your code ?

Answer 7

I ran his code . but the compiler said that :system was not declared in the scope.

but when I deleted it , the code ran well.

Answer 8

did you mean (system)will run well on pc ?

Answer 9

.... pause. prevents the console window from closing

Answer 10

https://code.sololearn.com/cjoF20p5GA98/?ref=app i've coded a similar thing, to transpose an input vertically.

Answer 11

😃

Answer 12

@Nguyên: lol. i knew there was an easier way

Answer 13

in codeplayground or on your pc

Answer 14

The program is written in visual studio. It means stopping the screen to see results

Answer 15

@Enas Emad I think if the input is a thousand characters, your way is a bit hard :v :V

Answer 16

@Enas Emad a thousand characters, no excess, no missing, great :p :p
Do you use social networking?
It would be great to be your friend
^^!

Answer 17

The question is already answered.