What are (void*) and static_cast<void*> ?

Question

i just learn pointer in C++ course. trying to get some memory address of variable. but when i want to get memory address of char, i have to use (void*) and static_cast<void*>.

what are they?
why i need them to get memory address of char?
and the most important can i use them for other purpose? like .... i don't know.
please give some simple explanation.

https://code.sololearn.com/crPAuWOTZgLt/?ref=app

Answer 1

@Setiawan Next, I used f because it lets the compiler know that 10.3 is a float number. By default 10.3 is a double unless you specify it as a float using f at the end of it (but you dont have to do that, your compiler will most likely see that you are assigning it to float and wont have to do a cast)

You can read a little about the difference between thise casts here: http://stackoverflow.com/questions/28002/regular-cast-vs-static-cast-vs-dynamic-cast

Answer 2

I don't think that f is needed. Only mentioning the data type will suffice.
Ya you can use that (int) type casting as shown in the example.

Answer 3

Those are casts into a void pointer. You dont need them to get the address of a char though. You can do that with the & operator instead, like so:

void* p = &myVar;

An example of a cast:

Float a = 10.3f;

Int b = static_cast<int>(a);

Which converts a into an int type

Answer 4

Ya aklex is right

Answer 5

thanks @Vishnu ks

Answer 6

thanks @aklex
can i ask a question again?
why you add f in the 10.3f ?

and can i use (int) to convert instead of static_cast<> like :

int b = (int)a;