What does this code mean?

Question

Int x;
X++ + ++x;
Cout<<x;

Answer 1

Hi Benyamin Rasouli
There is one syntax error in the code "Int" should be "int" and "X" should be "x".
Basically in the 2nd line x is incrementing first time using postfix increment operator (x++) and 2nd time by prefix increment operator (++x)
Basically in postfix increment it returns original value of the variable and then increment the value by 1
Whereas in prefix increment it increase the value by 1 and then returns the increased value .
So for above if we break the second line into two like this :
int x=0;
cout<<x++<<endl; //0
cout<<++x<<endl; //2
cout<<x;//2
So here at first it returns the original value of x which is 0 and then in next line when x is used it increase the value of x by 1 and then again due to prefix increment(++x) value of x again increased by 1 .
So final value of x is 2.
Hope that clears your doubt.