Exact square root

Question

#include <iostream>
using namespace std;

int main()
{
int num, sqr,i;
float temp, temp1,temp2;

cout<<"Enter the no: ";
cin>>num;

for(i=1;i<num/2;i++){
sqr=i*i;
if(sqr==num){
cout<<"Square root of "<<num<<" is "<<i;
break;
}

if(sqr>num){
i=i-1;
//temp2=(2*i);
//temp1=(num-i*i);
// temp=i+ temp1 /temp2;
temp=i+(num-i*i)/(2*i);
cout<<"Square root of "<<num<<" is "<<temp ;
break;
}
}
return 0;
}

Problem here is that if I will use temp1 and temp2 in temp then it return exact square root of any number but if I run temp without using temp1 and temp2 then it doesn't return exact value . Then exactly where is the problem

Answer 1

It depends of how works the compiler, that means the order of operations and used memory. This can be noticeable with very precise calculations.

Answer 2

Bro you are using builtin function but I don't want to use built-in function. I want to write my own function

Answer 3

Builtin functions are better practice actually but u must know how they actually

Answer 4

It actually uses binary search

Answer 5

https://sololearn.com/compiler-playground/cLGK1gOq2J8i/?ref=app