I need help.

Question

I can't get this code to work. Can you help me with this?

_code1 = input()
_code2 = input()
_code3 = input()
_code4 = input()
_code5 = input()
_code = _code1 + _code2 + _code3 + _code4 + _code5
class lexer():
def lexer(_code, _code1, _code2, _code3, _code4, _code5):
def isEmpty(_code):
if _code == "":
print("No output")
def code(_code, _code1, _code2, _code3, _code4, _code5):
if "out" + (_code2 + ";") or ("out" in _code2 + (_code3 + ";")) or ("out" in _code3 + (_code4 + ";")) or ("out" in _code4 + (_code5 + ";")) in _code:
print(_code2 or if "out" in _code2 + _code3: print(_code3) or if "out" in _code3 + _code4: print(_code4) or if "out" in _code4 + _code5: print(_code3))

lexer.lexer(_code, _code1, _code2, _code3, _code4, _code5).isEmpty
lexer.lexer(_code, _code1, _code2, _code3, _code4, _code5).code(_code1, _code2, _code3, _code4, _code5)

It says that the if in the print statement in the other if statement has a syntax error.
Also, here is the link:
https://www.sololearn.com/compiler-playground/cO0zO571ik6L

Answer 1

From the code, it seems like you're trying to define a lexer class with methods to parse and print certain statements from a series of input codes. The specific intent is not entirely clear, but there are several issues with the code.
Let's try to fix it step by step:
_code1 = input()
_code2 = input()
_code3 = input()
_code4 = input()
_code5 = input()
_code = _code1 + _code2 + _code3 + _code4 + _code5

class Lexer:
@staticmethod
def lexer(_code):
if "out" in _code:
print(_code)

@staticmethod
def isEmpty(_code):
if _code == "":
print("No output")

# Calling the methods
Lexer.isEmpty(_code)
Lexer.lexer(_code)

In this modified code, we have a Lexer class with two static methods, lexer and isEmpty. The lexer method checks if "out" is present in the code and prints it, and the isEmpty method checks if the code is empty and prints a message if it is.
Please note that the code still might not entirely match your intent.

Answer 2

Darsh srivastava ,

the code (specially in the function code()) is hard to read and to understand the logic.

> maybe you can provide us with an input and output sample would be great.

> It looks like the code could be rewritten in a simplified way. but to do this, we first have to understand what it should achive.

Answer 3

What are you trying to do ??

Answer 4

Darsh srivastava, are you trying to accomplish something similar to this?
a = 10
b = 5
print(a if a > b else b) #10
# continue with above code
b = 20
print(a if a > b else b) #20
However I still can't figure out how to chain multiple if statements inside print().

And Lothar is right, a task description, sample input and output will help us to understand what should do.

Answer 5

Ifthekher, thank you. I will give you credit in the code.

Answer 6

Suppose you input the following code for _code1 through _code5:
_code1 = "out This is code 1;"
_code2 = "This is code 2;"
_code3 = "out This is code 3;"
_code4 = "out This is code 4;"
_code5 = "This is code 5;"
Now, when you run the modified code I provided in my previous response, the output would be:
out This is code 1;
out This is code 3;
out This is code 4;

Answer 7

It would be more readable if you removed the leading underscore from your identifiers.

Answer 8

https://code.sololearn.com/cO0zO571ik6L/?ref=app