+ 2

a = [2, 3] b = [2, 6] a *= 3 b += 3 print(int(a is b))

25th Sep 2023, 3:08 PM
Unegbu Chidinma + 10
Python „is“ keyword is used to check if the memory reference of two Python objects are same or not. In the above example, the contents of a and b are same, but a and b are different objects having a different memory allocation. That returned int(False) = 0
25th Sep 2023, 3:20 PM
JaScript + 4
If id(a) == id(b) then ( a is b) returns true. Otherwise returns false.
25th Sep 2023, 3:25 PM
Jayakrishna 🇮🇳
+ 3
a = [2, 3] b = [2, 6] a *= 3 # a becomes [2, 9] b += 3 # b becomes [2, 9] Although both a and b represent [2, 9], they are pointing to different reference. To check the reference, we can use id() function. If you run below code: print(id(a)) print(id(b)) The output will not be the same. When we create 2 lists, they are pointing to difference reference. If you reassign one equal to another, then both will point to the same reference. x = [1, 2] y = [1, 2] # x and y have different id y = x # now y’s id is the same as x’s id Since a and b are pointing to different ids, running int(a is b) return False. And integer of False is 0, so it prints 0.
25th Sep 2023, 3:29 PM
Wong Hei Ming + 2
Thanks so much for the help.
25th Sep 2023, 3:34 PM
Unegbu Chidinma + 1
In python developer course, how we complete the code in Classes (the video game problem)?
25th Sep 2023, 8:19 PM
Anastasia Xydia 0
Becaus int(False) = 0
26th Sep 2023, 12:09 AM
Mikita Wagner 