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Question

/*Java - Can this be optimised even further -*/

import java.util.*;

public class Main {
public static void main(String[] args) {
Scanner scan = new Scanner(System.in);
String entry[] = new String[4];

for (int i = 0; i < entry.length; i++) {
entry[i] = scan.next().toUpperCase();
}

String[] reversed = new String[4];

for (int i = 0; i < entry.length; i++) {
char[] temp = entry[i].toCharArray();
char[] temp2 = new char[temp.length];

for (int j = 0; j < temp.length; j++) {
temp2[(temp.length - 1) - j] = temp[j];
}

reversed[i] = String.valueOf(temp2);
}

if (Arraycheck(entry, reversed)) {
System.out.println("Open");
} else
System.out.println("Trash");

}

static Boolean Arraycheck(String[] original, String[] reversed) {
for (int i = 0; i < original.length; i++) {
for (int j = 0; j < reversed.length; j++) {
if (original[i].equals(reversed[j])) {
return true;
}
}
}

return false;

}

}

Answer 1

That said, you can skip the creation of an array with reversed strings, and use a similar logic to compare each character with the one in the mirrored position.

Answer 2

Isuru what's your doubt?

Answer 3

Isuru Pls improve your question by:
1. Removing the wall of code in the question description, saving it in Code Playground, then adding a link to it (use "+" button) in the question description again.
2. Stating your requests in the question description too, not in an answer, where it can get lost if there are many others.

Answer 4

Hi Sakshi got any idea about writing the code using few lines.. I think code has too much lines