Why the output is 65 instead of 225 ?

Question

#include <stdio.h>
#define x 10+5
int main() {
int a = x*x;
printf("%d", a);
return 0;
}

Answer 1

SIMRAN

#define x 10 + 5 //here x = 10 + 5

So x * x = 10 + 5 * 10 + 5 = 10 + 50 + 5 = 65

-------

#define x (10 + 5) //here x = (10 + 5)

So x * x = (10 + 5) * (10 + 5) = 225

-------

#define x (10) + (5) //here x = (10) + (5)

So x * x = (10) + (5) * (10) + (5) = 10 + 50 + 5 = 65

Answer 2

10+5*10+5

Edit: you could instead #define x (10+5)

EDIT2: I think that define works before compilation, it does a (search replace) with the defined term definition.
eg if you 👉#define x 5👈
it may just replace xray to 5ray. Let's test that, I will report back what I find!

EDIT3: I don't think macro #define replaces letters when they are part of a longer word.

hmmm....
https://code.sololearn.com/cl05IIc37s4E/?ref=app

Answer 3

I got it , Thank you Ipang ,A͢J & HungryTradie 🤗❤️

Answer 4

x * x will be replaced with
10 + 5 * 10 + 5 which will be processed as
10 + ( 5 * 10 ) + 5 due to operator precedence (* priority is higher than +)

Hope it makes sense ...

Answer 5

Fff