What's the output of this code

Question

#include<stdio.h>
int main(){
int x;
for(x=-1; x<=10; x++){
if(x < 5)
continue;
else break;
printf("c programming");}
return 0;}

Answer 1

Oh. Sry i did not checked code clearly.. but mention question clearly..

#include<stdio.h>
int main() {

int x;
for(x=-1; x<=10; x++){
if(x < 5)
continue; //causes loop stop current iteration ,go with next iteration
else
break; //causes loop break
printf("c programming"); //never touched
}
return 0;
}

/*
initially x= -1, so x<=10
and next
x<5 is true, so continue with next iteration

x++ => x=0
x<5 is true, so continue with next iteration

x++ => x=1
x<5 is true, so continue with next iteration

x++ => x=2
x<5 is true, so continue with next iteration

x++ => x=3
x<5 is true, so continue with next iteration

x++ => x=4
x<5 is true, so continue with next iteration

x++ => x=5
x<5 is false, so goes to else and break cause to break the loop. so loop gets terminated here

Till now, and outside of loop, no output statements executed so no output....

edit:
saurav do you trying to get any output?
hope it clears..

Answer 2

Jayakrishna🇮🇳 it's showing no output ! Btw basically I want to know how output come
I mean logic behind 🤔it

Answer 3

Check in playground....

edit: