Uchta butun son berilgan. Shu sonlar orasidan nechta musbat son borligini aniqlovchi programma tuzilsin

Question

Shunga yordamlashvorila iltimos

Answer 1

juda osonku, berilgan sonlarni 0 dan katta ekanini tekshiring agar katta bo'lsa print qiling, kichik bo'lsa manfiy bo'ladi.

Answer 2

Ok thank you

Answer 3

If and Elif operatorlaridan foydalanib yozish kere man codeni yozdim tekshirib koʻrsam 3 ta musbot sonni chiqarib bermayapti

Answer 4

a = int(input("Birinchi sonni kiriting: "))
b = int(input("Ikkinchi sonni kiriting: "))
c = int(input("Uchinchi sonni kiriting: "))
if a and b >= 0 :
print ("Kiritilgan raqamlar orasida 2 ta musbat son bor")
elif b and c >= 0 or a and c >= 0:
print ("Kiritilgan raqamlar orasida 2 ta musbat son bor")
else:
print ("Kiritilgan raqamlar orasida musbat raqamlar soni 3 ta")

Answer 5

Oxirini hoz yozudim baribir xato chiqvoti

Answer 6

Omina Shavkatova
kodizni ham ko'rsata olasizmi

Answer 7

har birini alohida tekshiring,

a and b >= 0 emas a >= 0 and b >= 0...

Answer 8

Js dami bu cod

Answer 9

function myFunc(a,b,c) {
if (a > 0 && b > 0 && c > 0) {
console.log(`3ta musbat son bor`);
} else if(a > 0 && b > 0 ||b > 0 && c > 0 || a > 0 && c > 0 ) {
console.log(`2ta musbat son bor`);
} else if(a > 0 || b > 0 || c > 0) {
console.log(`1ta musbat son bor`);
}
}
myFunc(1,2,3)

mashi togri javob

Answer 10

Berilgan 5 ta son orasida nechta musbat, nechta manfiy va nechta nol qatnashganligini aniqlovchi dastur tuzing

Answer 11

asdfgh
hjhj

Answer 12

int a = input.nextInt ();
int b = input.nextInt ();
int c =input.nextInt ();
int d = 0;

if (a == 0) d++;
if (b == 0) d++;
if (c == 0) d++;
System.out.println (d + " ta nol bor");