Can anyone explain this code briefly?

Question

https://code.sololearn.com/cS8RMe8b7Vm5/?ref=app

Answer 1

A short piece of code, yet a bit hard to understand ryt.

a=[5,4,3,2,2,2,1]
print ( a[ a[ a[ a[2]+1 ] ] ])

First it gets the value of second index, which is 3. Then adds '1' to it. So it is, 4.
3+1=4

Then it gets the 4th index from the array, the value is 2.
Then it gets the 2nd index from the array, the value is 3.
Then it gets the value of 3rd index, which is 2.

The final answer is 2.

Answer 2

Steve Sajeev , thank you so much!

Answer 3

Given that the list 'a' contains [5,4,3,2,2,2,1]
The print statement contains a[a[a[a[2]+1]]]

The innermost square brackets will be evaluated first which is "a[2]"
a[2] = 3
And then it's "a[2]+1" = 3+1 =4
The second-most inner square bracket is a[a[2]+1] = a[4] = 2
The next inner bracket is a[a[a[2]+1] ] = a[2] = 3
The outermost bracket is a[a[a[a[2]+1] ]] = a[3] = 2
The result is the third element of the list which is true