Answer 1

Akkarawut 5105

The problem you have in your code is completely different to your original question.
However solution below using tuples and slicing via a boolean return of comparison operators

#Problem
#Do not use (if else)
#Write a program to calculate parking fees
'''
20 minutes free parking
1 hour 10 baht
2 hours later, the price is 20 baht/hour.
3 hours or more, 40 baht/hour
Fractions of minutes rounded up to hours.
(allowed to use "math.floor" and "math.ceil")

translated by Akkarawut 5105
'''

import math

time = int(input()) # in minutes
hrs = math.ceil(time/60)
rate = (hrs,4)[hrs >2]
fee = 0

for i in range(1,hrs+1):
fee += (0,rate *10)[time > 20]

print(("free",f'${fee}')[fee !=0])

Answer 2

You have any source or something to show the full question?

Answer 3

What you have tried so far?

Answer 4

Mine yours doesn't understand.

Answer 5

Akkarawut 5105
Are you sure it is not 0.25$ for 15 minutes.

Also is 7 minutes considered to be 15 minutes.

Is 16 minutes considered to be 30 minutes.

There is lots of missing info

Answer 6

Akkarawut 5105
Ok!, thanks

What would be the cost for 67 minutes?

I am still trying to get my head around the concept

Answer 7

Your question is not that clear reframe it well please

Answer 8

- take time as input.
- set sum = 0
- set time to time - 20 minutes (because the first 20 minutes are free)
- set time to time - 1 hour and add price for first hour to sum
- set time to time - x hours and add price for x hours to sum
- and so on until time is <= 0