+ 2

# Number of zeros at the end

Hello, can anyone tell me why this ist working? I have problem with while and return. number = 1802300 string_number = str(number) list = list(string_number) list.reverse() for i in range (len(list)): number_of_zero = 0 while i == 0: number_of_zero +=1 return number_of_zero It's telling me, that I have return outside function. But I don't know why?

15 Answers

+ 5

#try this
for i in list:
if i == '0':
number_of_zero +=1
else:
break
print(number_of_zero)

+ 5

#do you mean number of zero's at the end?
#If yes, then another way using while loop :
num = 1802300
number_of_zero =0
while not num%10:
number_of_zero +=1
num=num/10
print(number_of_zero)

+ 3

THIS IS WHAT YOU INTENDED TO DO.
1) return statement is for functions not for the loops, hence you are getting error
https://code.sololearn.com/cSK5ICH4UiLm/?ref=app

+ 3

#I can add another way
Str = input()
print(len(Str)-len(Str.rstrip('0')))
'''
*using built-in String methods
*total - removing the last 0 digits and finding length
*the same idea
'''

+ 1

number = 1802300
string_number = str(number)
list = list(string_number)
list.reverse() #you are dealing with string then no need to reverse here. you can directly work.
number_of_zero = 0 #make this outside of loop. inside loop cause reset to 0 every time
for i in list:
if i == '0': #you if block, ' while ' is a loop, just like for loop.
number_of_zero +=1
print(number_of_zero) # 'return' returns a value from function and comes out function but print() function displays output on screen.
#Hope it clears.. else reply..Jeanie Snow

+ 1

Thank you. But I need numbers of 0 after some different numbers.
Like for 1802300
I need the numbers of 0 after number 3.
This is why I tried reverse the list.
Because I wanted just count of 0 before number 3.

+ 1

Thank you very much.
I reverse the list and use this. And it's finally working.

+ 1

Yes.
Thank you very much.

+ 1

I just tried the task.
https://code.sololearn.com/ctfQdSKx2HwL

+ 1

Axel_
1) count method counts all zeros not only just the end zeroes(see your code)
2) NUMBER could be anything so slicing by just seeing the number won't be useful

0

You have while loop in infinite one.
What are you trying with that?
If while ,not work then it comes out for loop by return number_of_zero in first iteration. Then why need of loop ..? what the task you trying?

0

I have a number, for example 1300 .
And want to tell how many zeros are at the end.
So I convert int to str.
Like 1300 - > "1300"
then I want to separate the letters like
"1","3","0","0"
reverse them.
"0","0","3"1"
And then I would like to count the number of 0, which are before 3.
Like while number is zero. Count it.
Sorry for bad explanation.

0

Thank you very much.

0

Prabhas Koya your “idea” is awesome, especially using break statement for stopping “counting” nums of zeros!

0

#You can count last zeroes like this also
num=1802300
string_num=str(num)
c=0
for i in string_num[::-1]:
if i=="0":
c+=1
else:
break
print("Zeroes are",c)