What am I doing wrong here in the code? It's not showing any output

Question

You are working on a Contact Manager app.
You have created the contact object constructor, which has two arguments, name and number.
You need to add a print() method to the object, which will output the contact data to the console in the following format: name: number
The given code declares two objects and calls their print() methods. Complete the code by defining the print() method for the objects.
My code:.
function contact(name, number) {
this.name = name;
this.number = number;
this.print = function (anyName,anyNumber) {
this.name = anyName;
this.number = anyNumber ;
document.write(anyName+ ": " +anyNumber );

}
}

var a = new contact("David", 12345);
var b = new contact("Amy", 987654321);

a.print();
b.print();

Answer 1

Your print method wants 2 arguments but you entered 0

a.print("new Name", 123456);

Answer 2

Stefanoo I did this and still no output.
function contact(name, number) {
this.name = name;
this.number = number;
this.print = function (anyName,anyNumber) {
this.name = anyName;
this.number = anyNumber ;
document.write(anyName+ ": "+ anyNumber );

}
}

var a = new contact("David", 12345);
var b = new contact("Amy", 987654321);

a.print("David", 12345);
b.print("Amy", 987654321);

Answer 3

Sanja Panic bro I simply followed the Topic the project is based on

Answer 4

I deleted comment, because i checked and we can use function for this, class is added later.
I checked your last code and i can see result.

Answer 5

Sanja Panic Stefanoo thanks a lot but I have no idea why it was showing no output with document.write but did with console.log.

Code//////////
function contact(name, number) {
this.name = name;
this.number = number;
this.print = function (anyName,anyNumber) {
this.name = anyName;
this.number = anyNumber ;
console.log(anyName+ ": "+ anyNumber );

}
}

var a = new contact("David", 12345);
var b = new contact("Amy", 987654321);

a.print("David", 12345);
b.print("Amy", 987654321);

Answer 6

Anyways now it's working fine ,Thanks a lot a lot Stefanoo Sanja Panic