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How by using bitwise operators can you add numbers?

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11th Aug 2021, 3:25 PM
Yahel
Yahel - avatar
4 Answers
+ 1
In general by using bitwise OR operator. But, considering bitwise operator works at bit level, if the bit was already set, addition isn't happening. For example; BIN DEC 0001 1 0010 2 ------------ | (OR) 0011 3 0011 3 0010 2 ------------ | (OR) 0011 3 # no addition, bit (2) is already set P.S. I'm not too sure this was what you asked for, so perhaps you could elaborate further what it is in thread's Description.
11th Aug 2021, 3:56 PM
Ipang
+ 1
Yahel, This is in regards to C# but I guess it works pretty much the same in common languages. https://stackoverflow.com/questions/4068033/add-two-integers-using-only-bitwise-operators
11th Aug 2021, 4:25 PM
Ipang
0
Ipang you added 1 and 2 and you got 3 - as it should. When you added 3 and 2 - you got 3. I want to make it that I doesn't matter what 2 numbers I give as input, the output will be the sum of the numbers.
11th Aug 2021, 4:00 PM
Yahel
Yahel - avatar
0
You can do it similar to how the CPU does it: a = a ^ b b = (a & b) << 1 repeat until b is 0 or for the number of bits that you have
11th Aug 2021, 4:04 PM
Angelo
Angelo - avatar