Answer 1

because 'c', when used without an index as it is, is considered a pointer (or simply the array's starting place in memory) to the first value in the array.

when you use for instance, &<a variable with a single peice of data (ex. int n; scanf("%d", &n;))> you are really accessing the memory location of that variable.

So, in short, you dont use the & before 'c' in this case because 'c' is ALREADY a pointer (memory address)

Answer 2

In case of a string (character array), the variable itself points to the first element of the array in question. Thus, there is no need to use the '&' operator to pass the address. '&' is used to get the address of the variable.

src:-
https://www.google.com/amp/s/www.geeksforgeeks.org/not-used-strings-scanf-function/amp/

Any example code to what @Slick and I mentioned.
https://code.sololearn.com/cc6e9RnbX38D/?ref=app

Answer 3

Verstappen name is an array of characters which means its a "string", so you will need to do for it to be valid.

printf("%s", name);

%s is for string (or array of characters).
%c is for a single character.

*name = name[0]
*(name + 1) = name[1]
And we know both are a single character and hence this works
printf("%c", *name);
displaying the name[0] which is "s" in our example.